Math Practice Problems - Rectangular Solids 2

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Rectangular Solids 2 - Sample Math Practice Problems

The math problems below can be generated by MathScore.com, a math practice program for schools and individual families. References to complexity and mode refer to the overall difficulty of the problems as they appear in the main program. In the main program, all problems are automatically graded and the difficulty adapts dynamically based on performance. Answers to these sample questions appear at the bottom of the page. This page does not grade your responses.

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Complexity=4, Mode=word

Solve. Answer with proper units.

Complexity=6, Mode=word

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Complexity=8, Mode=word

Solve. Answer with proper units.

Complexity=10, Mode=word

Solve. Answer with proper units.

Complexity=12, Mode=word

Solve. Answer with proper units.

Answers

Complexity=3, Mode=word

Solve. Answer with proper units.

#	Problem	Correct Answer	Your Answer
1	The surface area of a rectangular solid is 24 m². The lengths of two of the sides are 2 m and 2 m. What is the length of the other side?	length =
Solution Surface Area = 2Lw + 2Lh + 2wh Pick h as the unknown (your choice doesn't matter) 24m² = (2 × 2m × 2m) + (2 × 2m × h) + (2 × 2m × h) 24m² = 8m² + (4 m)h + (4 m)h 16m² = (8 m)h 2m = h

#	Problem	Correct Answer	Your Answer
2	The volume of a rectangular solid is 6 m³. The length is 3 m and the height is 2 m. What is the width?	w =
Solution V = Lwh 6m³ = 3 × w × 2m 3m² = 3m × w 1m = w

Complexity=4, Mode=word

Solve. Answer with proper units.

#	Problem	Correct Answer	Your Answer
1	The surface area of a rectangular solid is 54 m². The lengths of two of the sides are 3 m and 3 m. What is the length of the other side?	length =
Solution Surface Area = 2Lw + 2Lh + 2wh Pick h as the unknown (your choice doesn't matter) 54m² = (2 × 3m × 3m) + (2 × 3m × h) + (2 × 3m × h) 54m² = 18m² + (6 m)h + (6 m)h 36m² = (12 m)h 3m = h

#	Problem	Correct Answer	Your Answer
2	The volume of a rectangular solid is 48 yd³. The length is 3 yd and the width is 4 yd. What is the height?	h =
Solution V = Lwh 48yd³ = 3yd × 4yd × h 16yd² = 4yd × h 4yd = h

Complexity=6, Mode=word

Solve. Answer with proper units.

#	Problem	Correct Answer	Your Answer
1	The surface area of a rectangular solid is 130 ft². The lengths of two of the sides are 5 ft and 4 ft. What is the length of the other side?	length =
Solution Surface Area = 2Lw + 2Lh + 2wh Pick h as the unknown (your choice doesn't matter) 130ft² = (2 × 5ft × 4ft) + (2 × 5ft × h) + (2 × 4ft × h) 130ft² = 40ft² + (10 ft)h + (8 ft)h 90ft² = (18 ft)h 5ft = h

#	Problem	Correct Answer	Your Answer
2	The volume of a rectangular solid is 54 in³. The length is 6 in and the height is 3 in. What is the width?	w =
Solution V = Lwh 54in³ = 6 × w × 3in 18in² = 6in × w 3in = w

Complexity=8, Mode=word

Solve. Answer with proper units.

#	Problem	Correct Answer	Your Answer
1	The surface area of a rectangular solid is 144 yd². The lengths of two of the sides are 3 yd and 6 yd. What is the length of the other side?	length =
Solution Surface Area = 2Lw + 2Lh + 2wh Pick h as the unknown (your choice doesn't matter) 144yd² = (2 × 3yd × 6yd) + (2 × 3yd × h) + (2 × 6yd × h) 144yd² = 36yd² + (6 yd)h + (12 yd)h 108yd² = (18 yd)h 6yd = h

#	Problem	Correct Answer	Your Answer
2	The volume of a rectangular solid is 54 m³. The width is 6 m and the height is 3 m. What is the length?	L =
Solution V = Lwh 54m³ = L × 6m × 3m 18m² = L × 6m 3m = L

Complexity=10, Mode=word

Solve. Answer with proper units.

#	Problem	Correct Answer	Your Answer
1	The surface area of a rectangular solid is 258 m². The lengths of two of the sides are 5 m and 6 m. What is the length of the other side?	length =
Solution Surface Area = 2Lw + 2Lh + 2wh Pick h as the unknown (your choice doesn't matter) 258m² = (2 × 5m × 6m) + (2 × 5m × h) + (2 × 6m × h) 258m² = 60m² + (10 m)h + (12 m)h 198m² = (22 m)h 9m = h

#	Problem	Correct Answer	Your Answer
2	The volume of a rectangular solid is 112 cm³. The width is 7 cm and the height is 4 cm. What is the length?	L =
Solution V = Lwh 112cm³ = L × 7cm × 4cm 28cm² = L × 7cm 4cm = L

Complexity=12, Mode=word

Solve. Answer with proper units.

#	Problem	Correct Answer	Your Answer
1	The surface area of a rectangular solid is 190 ft². The lengths of two of the sides are 9 ft and 2 ft. What is the length of the other side?	length =
Solution Surface Area = 2Lw + 2Lh + 2wh Pick h as the unknown (your choice doesn't matter) 190ft² = (2 × 9ft × 2ft) + (2 × 9ft × h) + (2 × 2ft × h) 190ft² = 36ft² + (18 ft)h + (4 ft)h 154ft² = (22 ft)h 7ft = h

#	Problem	Correct Answer	Your Answer
2	The volume of a rectangular solid is 162 yd³. The length is 6 yd and the height is 3 yd. What is the width?	w =
Solution V = Lwh 162yd³ = 6 × w × 3yd 54yd² = 6yd × w 9yd = w

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